Solving System of Equations Word Problems: Apples and Bananas
The Organic Chemistry TutorJanuary 5, 20264 min2,439 views
8 connectionsΒ·8 entities in this videoβSetting Up the Equations
- π Lauren's purchase is represented by the equation 8A + 9B = $9.25, where A is the price of an apple and B is the price of a banana.
- π Andrew's purchase is represented by the equation 7A + 6B = $7.25.
Solving for the Unit Price of an Apple
- π― To solve for the price of an apple (A), we aim to eliminate the variable B.
- βοΈ Multiply Lauren's equation by 2 and Andrew's equation by -3 to get a common multiple for B (18).
- β This results in -5A = -3.25, leading to an apple price (A) of $0.65.
Solving for the Unit Price of a Banana
- β Substitute the price of an apple ($0.65) back into Lauren's original equation (8A + 9B = $9.25).
- β This gives 8($0.65) + 9B = $9.25, simplifying to $5.20 + 9B = $9.25.
- β Subtracting $5.20 from both sides yields 9B = $4.05, resulting in a banana price (B) of $0.45.
Calculating the Final Cost
- π The problem asks for the cost of nine apples and seven bananas (9A + 7B).
- π° Using the calculated prices, 9($0.65) + 7($0.45) equals $5.85 + $3.15.
- β The total cost for Aaron to buy nine apples and seven bananas is $9.00.
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Whatβs Discussed
System of EquationsWord ProblemsAlgebraGED MathUnit PriceVariable EliminationSubstitution MethodLinear Equations
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