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Solving System of Equations Word Problems: Apples and Bananas

The Organic Chemistry TutorJanuary 5, 20264 min2,439 views
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Setting Up the Equations

  • 🍎 Lauren's purchase is represented by the equation 8A + 9B = $9.25, where A is the price of an apple and B is the price of a banana.
  • 🍌 Andrew's purchase is represented by the equation 7A + 6B = $7.25.

Solving for the Unit Price of an Apple

  • 🎯 To solve for the price of an apple (A), we aim to eliminate the variable B.
  • βœ–οΈ Multiply Lauren's equation by 2 and Andrew's equation by -3 to get a common multiple for B (18).
  • βž– This results in -5A = -3.25, leading to an apple price (A) of $0.65.

Solving for the Unit Price of a Banana

  • βž• Substitute the price of an apple ($0.65) back into Lauren's original equation (8A + 9B = $9.25).
  • βž– This gives 8($0.65) + 9B = $9.25, simplifying to $5.20 + 9B = $9.25.
  • βž— Subtracting $5.20 from both sides yields 9B = $4.05, resulting in a banana price (B) of $0.45.

Calculating the Final Cost

  • πŸ›’ The problem asks for the cost of nine apples and seven bananas (9A + 7B).
  • πŸ’° Using the calculated prices, 9($0.65) + 7($0.45) equals $5.85 + $3.15.
  • βœ… The total cost for Aaron to buy nine apples and seven bananas is $9.00.
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What’s Discussed

System of EquationsWord ProblemsAlgebraGED MathUnit PriceVariable EliminationSubstitution MethodLinear Equations
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