Solving Rational Inequalities: Testing Intervals with Rational Expressions
Khan AcademyJanuary 13, 20267 min8,319 views
12 connectionsΒ·17 entities in this videoβRewriting the Inequality
- π― The first step is to rewrite the inequality so that one side is zero, allowing for interval testing.
- π‘ This involves algebraic manipulation, such as subtracting terms from both sides to achieve the zero.
Simplifying the Rational Expression
- π οΈ Combine terms into a single rational expression by finding a common denominator.
- β οΈ Be mindful of removable discontinuities (e.g., where a factor cancels from numerator and denominator), noting these as restrictions on the domain (e.g., x cannot equal -2).
- π§© After combining terms, simplify the numerator and denominator. For example, x^2 terms may cancel out.
Identifying Critical Points
- π Critical points for sign changes are where the numerator equals zero or where there are non-removable discontinuities (where the denominator equals zero).
- π In this case, the critical points are x = 2 (from the numerator 2x - 4) and x = -3 (from the denominator x + 3).
Testing Intervals
- π Test intervals defined by the critical points to determine where the rational expression is greater than or equal to zero.
- π§ͺ For x < -3 (e.g., x = -4), the expression is positive.
- π§ͺ For -3 < x < 2 (e.g., x = 0), the expression is negative.
- π§ͺ For x > 2 (e.g., x = 3), the expression is positive.
Solution Set
- β The solution set includes intervals where the expression is positive or zero.
- π This includes x < -3 and x β₯ 2.
- π The solution can be expressed in interval notation as (-β, -3) U [2, β), remembering the domain restriction x β -2.
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17 entities
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Transcript29 segments
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Topics13 themes
Whatβs Discussed
Rational InequalitiesInterval TestingRational ExpressionsAlgebraic ManipulationCommon DenominatorRemovable DiscontinuitiesNon-removable DiscontinuitiesNumeratorDenominatorSign ChangesDomain RestrictionsSolution SetInterval Notation
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