Probability of Drawing Two Red Hearts Without Replacement (GED Math)
The Organic Chemistry TutorJanuary 15, 20262 min4,030 views
2 connectionsยท3 entities in this videoโCalculating Probability Without Replacement
- ๐ฏ The problem asks for the probability of drawing two red hearts consecutively from a standard 52-card deck without putting the first card back.
- ๐ก Understanding the composition of a standard deck is key: 52 total cards, with 13 red hearts.
Probability of the First Draw
- ๐ For the first draw, there are 13 red hearts out of a total of 52 cards.
- ๐ The probability of drawing a red heart on the first try is therefore 13/52.
Probability of the Second Draw
- โ ๏ธ Since the first card is not replaced, there are now only 51 cards left in the deck.
- ๐ If the first card drawn was a red heart, there are now only 12 red hearts remaining.
- ๐ The probability of drawing a second red heart, given the first was a red heart, is 12/51.
Final Probability Calculation
- ๐งฎ To find the probability of both events happening, we multiply the probabilities of each draw: (13/52) * (12/51).
- ๐ Simplifying the fractions: (13/52) simplifies to 1/4, and (12/51) simplifies to 4/17.
- โ Multiplying the simplified fractions (1/4) * (4/17) results in 4/68, which further simplifies to 1/17.
- ๐ The final probability of drawing two red hearts without replacement is 1 out of 17.
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ProbabilityStandard Deck of CardsRed HeartsWithout ReplacementGED MathCard Drawing ProbabilityConditional Probability
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