Calculating Surface Area of a Regular Octagonal Pyramid
Khan AcademySeptember 6, 20257 min2,036 views
5 connections·10 entities in this video→Lateral Surface Area Calculation
- 🎯 The goal is to find the lateral surface area of a right pyramid with a regular octagon base.
- 💡 To calculate this, we need the surface area of each of the eight triangular faces.
- 📐 The base of each triangular face is given as 6 meters, and we need to find its height (slant height of the pyramid face), referred to as 'h'.
- 📐 To find 'h', we use the Pythagorean theorem, which requires knowing the distance 'x' from the center of the octagon to the midpoint of a base side, and the pyramid's height (9 meters).
- 📐 The value of 'x' is found using trigonometry:
x = 3 / tan(22.5°), derived from the angle of the octagon's central triangles. - ⚡ The lateral surface area is then calculated as
8 * (1/2 * base * h), substituting the derived 'h' and base (6m). - 📊 The approximate lateral surface area is 277 square meters.
Total Surface Area Calculation
- ➕ To find the total surface area, we need to add the area of the octagonal base to the lateral surface area.
- 📐 The area of the octagonal base can be calculated by summing the areas of the eight triangles that form it, each with a base of 6 meters and a height of 'x' (3 / tan(22.5°)).
- 🧮 The area of one such triangle is
1/2 * 6 * (3 / tan(22.5°)), and the total base area is8 * (1/2 * 6 * (3 / tan(22.5°))). - 📈 The total surface area is the sum of the lateral surface area and the calculated base area.
- 📍 The approximate total surface area is 451 square meters.
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Transcript27 segments
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What’s Discussed
Surface AreaOctagonal PyramidLateral Surface AreaTotal Surface AreaRegular OctagonRight PyramidTrigonometryPythagorean TheoremGeometryArea of a TriangleArea of a Polygon
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